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PERLLOL(1)                            Perl Programmers Reference Guide                            PERLLOL(1)



NAME
       perllol - Manipulating Arrays of Arrays in Perl

DESCRIPTION
   Declaration and Access of Arrays of Arrays
       The simplest thing to build is an array of arrays (sometimes imprecisely called a list of lists).
       It's reasonably easy to understand, and almost everything that applies here will also be applicable
       later on with the fancier data structures.

       An array of an array is just a regular old array @AoA that you can get at with two subscripts, like
       $AoA[3][2].  Here's a declaration of the array:

           # assign to our array, an array of array references
           @AoA = (
                  [ "fred", "barney" ],
                  [ "george", "jane", "elroy" ],
                  [ "homer", "marge", "bart" ],
           );

           print $AoA[2][2];
         bart

       Now you should be very careful that the outer bracket type is a round one, that is, a parenthesis.
       That's because you're assigning to an @array, so you need parentheses.  If you wanted there not to be
       an @AoA, but rather just a reference to it, you could do something more like this:

           # assign a reference to array of array references
           $ref_to_AoA = [
               [ "fred", "barney", "pebbles", "bambam", "dino", ],
               [ "homer", "bart", "marge", "maggie", ],
               [ "george", "jane", "elroy", "judy", ],
           ];

           print $ref_to_AoA->[2][2];

       Notice that the outer bracket type has changed, and so our access syntax has also changed.  That's
       because unlike C, in perl you can't freely interchange arrays and references thereto.  $ref_to_AoA is
       a reference to an array, whereas @AoA is an array proper.  Likewise, $AoA[2] is not an array, but an
       array ref.  So how come you can write these:

           $AoA[2][2]
           $ref_to_AoA->[2][2]

       instead of having to write these:

           $AoA[2]->[2]
           $ref_to_AoA->[2]->[2]

       Well, that's because the rule is that on adjacent brackets only (whether square or curly), you are
       free to omit the pointer dereferencing arrow.  But you cannot do so for the very first one if it's a
       scalar containing a reference, which means that $ref_to_AoA always needs it.

   Growing Your Own
       That's all well and good for declaration of a fixed data structure, but what if you wanted to add new
       elements on the fly, or build it up entirely from scratch?

       First, let's look at reading it in from a file.  This is something like adding a row at a time.
       We'll assume that there's a flat file in which each line is a row and each word an element.  If
       you're trying to develop an @AoA array containing all these, here's the right way to do that:

           while (<>) {
               @tmp = split;
               push @AoA, [ @tmp ];
           }

       You might also have loaded that from a function:

           for $i ( 1 .. 10 ) {
               $AoA[$i] = [ somefunc($i) ];
           }

       Or you might have had a temporary variable sitting around with the array in it.

           for $i ( 1 .. 10 ) {
               @tmp = somefunc($i);
               $AoA[$i] = [ @tmp ];
           }

       It's very important that you make sure to use the "[]" array reference constructor.  That's because
       this will be very wrong:

           $AoA[$i] = @tmp;

       You see, assigning a named array like that to a scalar just counts the number of elements in @tmp,
       which probably isn't what you want.

       If you are running under "use strict", you'll have to add some declarations to make it happy:

           use strict;
           my(@AoA, @tmp);
           while (<>) {
               @tmp = split;
               push @AoA, [ @tmp ];
           }

       Of course, you don't need the temporary array to have a name at all:

           while (<>) {
               push @AoA, [ split ];
           }

       You also don't have to use push().  You could just make a direct assignment if you knew where you
       wanted to put it:

           my (@AoA, $i, $line);
           for $i ( 0 .. 10 ) {
               $line = <>;
               $AoA[$i] = [ split ' ', $line ];
           }

       or even just

           my (@AoA, $i);
           for $i ( 0 .. 10 ) {
               $AoA[$i] = [ split ' ', <> ];
           }

       You should in general be leery of using functions that could potentially return lists in scalar
       context without explicitly stating such.  This would be clearer to the casual reader:

           my (@AoA, $i);
           for $i ( 0 .. 10 ) {
               $AoA[$i] = [ split ' ', scalar(<>) ];
           }

       If you wanted to have a $ref_to_AoA variable as a reference to an array, you'd have to do something
       like this:

           while (<>) {
               push @$ref_to_AoA, [ split ];
           }

       Now you can add new rows.  What about adding new columns?  If you're dealing with just matrices, it's
       often easiest to use simple assignment:

           for $x (1 .. 10) {
               for $y (1 .. 10) {
                   $AoA[$x][$y] = func($x, $y);
               }
           }

           for $x ( 3, 7, 9 ) {
               $AoA[$x][20] += func2($x);
           }

       It doesn't matter whether those elements are already there or not: it'll gladly create them for you,
       setting intervening elements to "undef" as need be.

       If you wanted just to append to a row, you'd have to do something a bit funnier looking:

           # add new columns to an existing row
           push @{ $AoA[0] }, "wilma", "betty";

       Notice that I couldn't say just:

           push $AoA[0], "wilma", "betty";  # WRONG!

       In fact, that wouldn't even compile.  How come?  Because the argument to push() must be a real array,
       not just a reference to such.

   Access and Printing
       Now it's time to print your data structure out.  How are you going to do that?  Well, if you want
       only one of the elements, it's trivial:

           print $AoA[0][0];

       If you want to print the whole thing, though, you can't say

           print @AoA;         # WRONG

       because you'll get just references listed, and perl will never automatically dereference things for
       you.  Instead, you have to roll yourself a loop or two.  This prints the whole structure, using the
       shell-style for() construct to loop across the outer set of subscripts.

           for $aref ( @AoA ) {
               print "\t [ @$aref ],\n";
           }

       If you wanted to keep track of subscripts, you might do this:

           for $i ( 0 .. $#AoA ) {
               print "\t elt $i is [ @{$AoA[$i]} ],\n";
           }

       or maybe even this.  Notice the inner loop.

           for $i ( 0 .. $#AoA ) {
               for $j ( 0 .. $#{$AoA[$i]} ) {
                   print "elt $i $j is $AoA[$i][$j]\n";
               }
           }

       As you can see, it's getting a bit complicated.  That's why sometimes is easier to take a temporary
       on your way through:

           for $i ( 0 .. $#AoA ) {
               $aref = $AoA[$i];
               for $j ( 0 .. $#{$aref} ) {
                   print "elt $i $j is $AoA[$i][$j]\n";
               }
           }

       Hmm... that's still a bit ugly.  How about this:

           for $i ( 0 .. $#AoA ) {
               $aref = $AoA[$i];
               $n = @$aref - 1;
               for $j ( 0 .. $n ) {
                   print "elt $i $j is $AoA[$i][$j]\n";
               }
           }

   Slices
       If you want to get at a slice (part of a row) in a multidimensional array, you're going to have to do
       some fancy subscripting.  That's because while we have a nice synonym for single elements via the
       pointer arrow for dereferencing, no such convenience exists for slices.  (Remember, of course, that
       you can always write a loop to do a slice operation.)

       Here's how to do one operation using a loop.  We'll assume an @AoA variable as before.

           @part = ();
           $x = 4;
           for ($y = 7; $y < 13; $y++) {
               push @part, $AoA[$x][$y];
           }

       That same loop could be replaced with a slice operation:

           @part = @{ $AoA[4] } [ 7..12 ];

       but as you might well imagine, this is pretty rough on the reader.

       Ah, but what if you wanted a two-dimensional slice, such as having $x run from 4..8 and $y run from 7
       to 12?  Hmm... here's the simple way:

           @newAoA = ();
           for ($startx = $x = 4; $x <= 8; $x++) {
               for ($starty = $y = 7; $y <= 12; $y++) {
                   $newAoA[$x - $startx][$y - $starty] = $AoA[$x][$y];
               }
           }

       We can reduce some of the looping through slices

           for ($x = 4; $x <= 8; $x++) {
               push @newAoA, [ @{ $AoA[$x] } [ 7..12 ] ];
           }

       If you were into Schwartzian Transforms, you would probably have selected map for that

           @newAoA = map { [ @{ $AoA[$_] } [ 7..12 ] ] } 4 .. 8;

       Although if your manager accused you of seeking job security (or rapid insecurity) through
       inscrutable code, it would be hard to argue. :-) If I were you, I'd put that in a function:

           @newAoA = splice_2D( \@AoA, 4 => 8, 7 => 12 );
           sub splice_2D {
               my $lrr = shift;        # ref to array of array refs!
               my ($x_lo, $x_hi,
                   $y_lo, $y_hi) = @_;

               return map {
                   [ @{ $lrr->[$_] } [ $y_lo .. $y_hi ] ]
               } $x_lo .. $x_hi;
           }

SEE ALSO
       perldata, perlref, perldsc

AUTHOR
       Tom Christiansen <tchrist@perl.com>

       Last update: Thu Jun  4 16:16:23 MDT 1998



perl v5.12.5                                     2012-11-03                                       PERLLOL(1)