tf.sets.difference

Вычисление разности множеств элементов в последнем измерении a и b.

tf.sets.difference(
    a, b, aminusb=True, validate_indices=True
)

Все измерения, кроме последнего, у a и b должны совпадать.

Пример:

import tensorflow as tf
import collections

# Represent the following array of sets as a sparse tensor:
# a = np.array([[{1, 2}, {3}], [{4}, {5, 6}]])
a = collections.OrderedDict([
    ((0, 0, 0), 1),
    ((0, 0, 1), 2),
    ((0, 1, 0), 3),
    ((1, 0, 0), 4),
    ((1, 1, 0), 5),
    ((1, 1, 1), 6),
])
a = tf.sparse.SparseTensor(list(a.keys()), list(a.values()),
                           dense_shape=[2, 2, 2])

# np.array([[{1, 3}, {2}], [{4, 5}, {5, 6, 7, 8}]])
b = collections.OrderedDict([
    ((0, 0, 0), 1),
    ((0, 0, 1), 3),
    ((0, 1, 0), 2),
    ((1, 0, 0), 4),
    ((1, 0, 1), 5),
    ((1, 1, 0), 5),
    ((1, 1, 1), 6),
    ((1, 1, 2), 7),
    ((1, 1, 3), 8),
])
b = tf.sparse.SparseTensor(list(b.keys()), list(b.values()),
                           dense_shape=[2, 2, 4])

# `set_difference` is applied to each aligned pair of sets.
tf.sets.difference(a, b)

# The result will be equivalent to either of:
#
# np.array([[{2}, {3}], [{}, {}]])
#
# collections.OrderedDict([
#     ((0, 0, 0), 2),
#     ((0, 1, 0), 3),
# ])