Spec-Zone .ru
спецификации, руководства, описания, API
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Task: Find the number, dealer, and price of the most expensive article.
This is easily done with a subquery:
SELECT article, dealer, priceFROM shopWHERE price=(SELECT MAX(price) FROM shop);+---------+--------+-------+| article | dealer | price |+---------+--------+-------+| 0004 | D | 19.95 |+---------+--------+-------+
Other solutions are to use a LEFT JOIN
or to sort all rows descending by price and
get only the first row using the MySQL-specific LIMIT
clause:
SELECT s1.article, s1.dealer, s1.priceFROM shop s1LEFT JOIN shop s2 ON s1.price < s2.priceWHERE s2.article IS NULL;SELECT article, dealer, priceFROM shopORDER BY price DESCLIMIT 1;
If there were several most expensive articles, each with a price of 19.95, the LIMIT
solution would show only one of them.